x^2+95x=1650

Solution for x^2+95x=1650 equation:

x^2+95x=1650

We move all terms to the left:

x^2+95x-(1650)=0

a = 1; b = 95; c = -1650;
Δ = b2-4ac
Δ = 952-4·1·(-1650)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-125}{2*1}=\frac{-220}{2}
=-110
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+125}{2*1}=\frac{30}{2}
=15
$